Some pandas trick

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Import an [sqlalchemy] table to a [pandas] dataframe

table_df = pd.read_sql(
           'SELECT * from game',
           session_remote.bind
           )

How to calculate summary statistics

Aggregating statistics

titanic["Age"].mean()
Out[4]: 29.69911764705882

titanic[["Age", "Fare"]].median()
Out[5]:
Age     28.0000
Fare    14.4542
dtype: float64
titanic[["Age", "Fare"]].describe()
Out[6]:
              Age        Fare
count  714.000000  891.000000
mean    29.699118   32.204208
std     14.526497   49.693429
min      0.420000    0.000000
25%     20.125000    7.910400
50%     28.000000   14.454200
75%     38.000000   31.000000
max     80.000000  512.329200

# or
titanic.agg(
    {
        "Age": ["min", "max", "median", "skew"],
        "Fare": ["min", "max", "median", "mean"],
    }
)

Out[7]:
              Age        Fare
min      0.420000    0.000000
max     80.000000  512.329200
median  28.000000   14.454200
skew     0.389108         NaN
mean          NaN   32.204208

Aggregating statistics grouped by category

Aggregating statistics grouped by category

titanic[["Sex", "Age"]].groupby("Sex").mean()
Out[8]:
              Age
Sex
female  27.915709
male    30.726645

more about this

Count number of records by category

titanic["Pclass"].value_counts()
Out[12]:
3    491
1    216
2    184
Name: Pclass, dtype: int64

# or
titanic.groupby("Pclass")["Pclass"].count()
Out[13]:
Pclass
1    216
2    184
3    491
Name: Pclass, dtype: int64

How to calculate summary statistics

How do I select rows from a DataFrame based on column values

df.loc[df['column_name'] == some_value]

df.loc[df['column_name'].isin(some_values)]

df.loc[(df['column_name'] >= A) & (df['column_name'] <= B)]
# Note the parentheses. Due to Python's operator precedence rules, & binds more tightly than <= and >=. Thus, the parentheses in the last example are necessary. Without the parentheses

df.loc[df['column_name'] != some_value]

df.loc[~df['column_name'].isin(some_values)]

source

How to select rows with one or more nulls from a pandas DataFrame without listing columns explicitly

In [60]: df[pd.isnull(df).any(axis=1)]
Out[60]:
   0   1   2
1  0 NaN   0
2  0   0 NaN

sourse

Set value of one column based on value in another column

df.loc[df['c1'] == 'Value', 'c2'] = 10

more examples

Replacing Rows in Pandas DataFrame with Other DataFrame Based on Index

df1.update(df2)
>>> df1
       B     C
A
0  300.0   6.0
1  400.0   7.0
2  433.0  99.0
3  555.0  99.0

Or use df1.combine_first(df2). Source

Deleting DataFrame row in Pandas based on column value

df = df[df.line_race != 0]

more examples

Use [tqdm] Progress Bar with Pandas

for index, row in tqdm(df.iterrows(), total=df.shape[0]):
   print("index",index)
   print("row",row)

source

Most straightforward row iteration with [pandas]

df = sns.load_dataset('iris')
for index, row in df.iterrows():
    print(row, '\n')

# or itertuples()
species_labels = {'setosa': 0, 'versicolor': 1, 'virginica': 2}

for row in df.itertuples():
    label = species_labels[row.species]
    df['species'].at[row.Index] = label # update the row in the dataframe

# or apply()
species_labels = {'setosa': 0, 'versicolor': 1, 'virginica': 2}

df['species'] = df.apply(lambda row: species_labels[row['species']], axis=1)

# or map()
species_labels = {'setosa': 0, 'versicolor': 1, 'virginica': 2}

df['species'] = df['species'].map(species_labels)

source

How to show PIL Image in ipython notebook

from IPython.display import Image
pil_img = Image(filename='data/empire.jpg')
display(pil_img)

# or
from matplotlib.pyplot import imshow
import numpy as np
from PIL import Image

%matplotlib inline
pil_im = Image.open('data/empire.jpg', 'r')
imshow(np.asarray(pil_im))

# or
from PIL import Image               # to load images
from IPython.display import display # to display images

pil_im = Image.open('path/to/image.jpg')
display(pil_im)

source

IPython Notebook output cell is truncating contents of my list

pd.options.display.max_rows = 4000

This can be used as context. Source

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